sanjuan
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Thanx, i'm really glad to heard it!lol Europeans, "Sorry about my English"
*asks technical questions in perfect English*
Hi, i'm not doubting in your words but as you can see heremouser says in item description: "Dimming: Without Dimming "The data sheet and reality says the enclosed model (for sure) is dimmable by an internal pot. I don't see any info that excludes the bare board version. http://www.meanwell-bg.com/files/M2015H2/HBG-60-spec.pdf
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If you can use less paste that would be better. I use a thin plastic sheet to spread a very thin layer, maybe half as think as what you are doing. nice work
I used a credit card to spread and a lot stays on that. I wasn't going to CPU type thinness because the heatsinks have varying amounts of waviness. But good point, thinner is better.If you can use less paste that would be better. I use a thin plastic sheet to spread a very thin layer, maybe half as think as what you are doing. nice work
I am cheap lolI used a credit card to spread and a lot stays on that. I wasn't going to CPU type thinness because the heatsinks have varying amounts of waviness. But good point, thinner is better.
Sire, i agree! How cold measure 1.4 A out from a hbg-100? Surely by a tester but how?The HBG-100 series will bolt onto the Mega heatsink as you say, there are tapped holes for both the 98mm HBG-60 hole pattern and the 113mm diameter hole pattern of the HBG-100.
The HBG-100-48A would be my choice for 36V COBs. The A model's internal pot adjusts current from 1.2 to 2A. The metal case is a good upgrade from the plastic HBG-60. Efficiency is good all the way towards 50% load for 120VAC operation. I think the HBG-100 is a good choice; I was thinking about trying one out but I don't need any more photons.
So on hbg-60 sn't there any "end of scale" for dimm at full power? Your is a smart method but as you sayd a little bit rough..The current can be measured with a multimeter but you need to connect the meter in series with the COBs. Youtubes can show how to measure current directly.
I estimate output current indirectly by using a Killawatt meter on a 120VAC circuit and subtract the fan (if present) and driver losses. As a rough example, 36V x 1.4A = 50.4W. As I recall, the driver is about 91% efficient. 50.4W divided by 91% is 55.4W--I'd adjust the pot so 55 watts is drawn from the electrical outlet.