How to wire a POT on HLG-320H

R

rocho

Well-Known Member
Hello to everybody, i'm going to buy a MeanWell HLG-320H-C1400 to drive 5 CLU 048.
I'd like to buy the B version instead the A because i think the internal screw is not so practical in current use. Could somebody help me to find the right Potentiometer to buy (1-10 V? 0-10V) maybe linking me that on ebay or mouser? I m really bad in electronic knowledge(and as you can see in english leanguage) but i want to be perseverant. Watching some video on youtube i m quite confuse.
Many thanx
 
R

rocho

Well-Known Member
JavaCo

JavaCo

Well-Known Member
rocho said:
Hi, thanx you both. Could i use any 100k potentiometer?
For example which of the following, if any?
Best regards(topcat thanx for your suggest but m looking for an european seller)

http://www.ebay.com/itm/BOURNS-Prazisionspotentiomer-3590S-1K-5K-10K-47K-100K-Ohm-Potentiometer-10KR-2W-/321976303071?var=&hash=item4af7487ddf:m:mUi0PPPoJDF_NEYgEB6M8fQ


http://www.ebay.com/itm/Potenziometro-100K-lineare-15mm-Potentiometer-/152157679449?hash=item236d4def59:g:tZwAAOSwkl5XfV3G
Click to expand...
Get the first one the ten turn, They are much nicer. But yes any linear 100K pot will work.
 
R

rocho

Well-Known Member
JavaCo said:
Get the first one the ten turn, They are much nicer. But yes any linear 100K pot will work.
Click to expand...
Thank you again! Will it difficult wire the pot to the driver? There are 4 wire out from the driver: + and - for the COBs and other two wire for the pot...i have only to sold those two wires (dim+ and dim-)to the potentiometer or there is a particular scheme i must to follow? I'm really ignorant, sorry.
 
R

rocho

Well-Known Member
Then i ve just find this 3d and I'm a little confuse...i must I add a resistor to have a 100% outpunt current?
What could happen dimming the driver below 10%?
Zulunature said:
One wire to the middle pin and one to either the left or right pin (this will determine clock or anti clockwise rotation of knob increasing or decreasing output)... sorry can't recall which does what...

Negative (black) to the outside...

Oh and add a resistor to the negative side of 10K so that it doesn't go below 10% output as recommended by Meanwell and increases the output of the Pot. at the top end as most only go to 90-96K with the 10K in series you should get the maximum 100K output.
Click to expand...
 
JavaCo

JavaCo

Well-Known Member
rocho said:
Thank you again! Will it difficult wire the pot to the driver? There are 4 wire out from the driver: + and - for the COBs and other two wire for the pot...i have only to sold those two wires (dim+ and dim-)to the potentiometer or there is a particular scheme i must to follow? I'm really ignorant, sorry.
Click to expand...
rocho said:
Then i ve just find this 3d and I'm a little confuse...i must I add a resistor to have a 100% outpunt current?
What could happen dimming the driver below 10%?
Click to expand...
Pretty easy to wire up there is a thread in here on how to do it. I would wire in a switch to get 100% output. Leaving the dim wires open will usually give the driver a little boost past rated specs of the driver. So flipping a switch to the off position that's wired into a dimmer wire will open the circuit giving you a boost. The couple times i have dimmed below 10% nothing happened. I try to not go below 33% dimming as efficiency goes to hell right in there. But yeah you can wire in a 10K resistor to stop it from going below 10%.
 
R

rocho

Well-Known Member
Thanx for your help, unfortuantely my engkish is not so good. Arebyou sayng me that should use switch plus a potentiometer so if i need i could have some extea power that with only potentiometer i could ot get? Isn t it? Is it difficoult to do? That should bereally important for my diy lamp project because of volt current of my clu 048 1212 wire in series at 1.4A will give me a little more volts than driver output..
 
JavaCo

JavaCo

Well-Known Member
Switches are pretty easy. You just need to do one of the dim wires with a single pole switch. Off is the same as open So when switched to the off position the driver will usually give a little bit more current then if the pot was hooked up dialed all the way up to 100K. Thats pretty much it,one side of the switch goes to one of the DIM wires and the other goes to one prongs on the Pot. Switch on for dimming ,switch off for full blast.
 
R

rocho

Well-Known Member
JavaCo said:
Switches are pretty easy. You just need to do one of the dim wires with a single pole switch. Off is the same as open So when switched to the off position the driver will usually give a little bit more current then if the pot was hooked up dialed all the way up to 100K. Thats pretty much it,one side of the switch goes to one of the DIM wires and the other goes to one prongs on the Pot. Switch on for dimming ,switch off for full blast.
Click to expand...
Really kindly from you, i ll try to do that...not sure to have understand but you have tried your best so many many thanx...i must to find an easy step by step tutorial.
 
R

rocho

Well-Known Member
topcat said:
https://www.rollitup.org/t/meanwell-led-drivers-3-in-1-dimming-function.838760/page-11#post-13304570

This is what you want to read. Well, start at the beginning.
Click to expand...
Thax! I m reading lots of informatioms, a reallynusefull 3d..
JavaCo said:
Switches are pretty easy. You just need to do one of the dim wires with a single pole switch. Off is the same as open So when switched to the off position the driver will usually give a little bit more current then if the pot was hooked up dialed all the way up to 100K. Thats pretty much it,one side of the switch goes to one of the DIM wires and the other goes to one prongs on the Pot. Switch on for dimming ,switch off for full blast.
Click to expand...
I got it! You re right..it seems not hard to do..great idea!!
I found a 100k pot with an integrate switch...if I m right that should has a fourth connector for switch function, isn t it? Or maybe switch is built on and i have only to wire it like a classic pot? Should be a good solution?
http://www.ebay.com/itm/1-5-10-20-50-100-500-K-M-ohm-Linear-Logarithmic-Mono-Stereo-Pot-Potentiometer-st-/180988727596?var=&hash=item2a23c4d12c:m:mSeUFwhBM2w8PnYD2qmXXSA
If I m right do you know how could i wire it?
 
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