...Thanks Supra... ...one question more...
Grow Area: 4’ x 4’ = 16 sq-ft = 1,49 M2
Grow Area: 4’ x 4’ = 16 sq-ft = 1,48644864 M2
Grow Area: 3’ x 3’ = 9 sq-ft = 0,84 M2
Grow Area: 3’ x 3’ = 9 sq-ft = 0,83612736 M2
Grow Area: 2’ x 2’ = 4 sq-ft = 0,37 M2
Grow Area: 2’ x 2’ = 4 sq-ft = 0,37161216 M2
At full blast 1,4 A
CXB3070 3K AD @ 1,4 A = 49.8 W @ 48 % Efficient = 23,9 PAR W
23,9 PAR W * 16 COBs = 382,5 PAR W
382,5 PAR W -10 % losses to lens / reflector / scatter = 344,25 PAR W
344,25 PAR W / 16 ft² = 21,5 PAR W / ft²
21,5 PAR W * 4,66 uMol / S * 10,7 = 1072 µMol M2 S (PPFD).
...my way in blue... ...its this correct ???...
344,25 PAR W / 1,49 M2 = 231,04 PAR W / M² ...............................??????
231,04 PAR W / M² * 4.66 uMol / S = 1076,65 µMol / M2 S (PPFD) .........??????
...other way from PPF to PPFD...
...from Gavita... (Lumens are for Human)...
Calculations made with 10 % reflector / wall losses:
a) - Philips GreenPower 400 W 230 V - PPF 725 µMol / S
400 W a) – 1 m x 1 m - 1 M2 at a PPFD of ~ 650 µMol / M2 S
b) - Philips GreenPower 600 W 230 V - PPF 1100 µMol / S
600 W b) - 1,2 m x 1,2 m - 1,44 M2 at a PPFD of ~ 690 µMol / M2 S
c) - Philips GreenPower 1000 W 400 V Electronic - PPF 2000 µMol
1000 W c) - 1,5 m x 1,5 m - 2,25 M2 at a PPFD of ~ 800 µMol / M2 S
.............................................................
...from Indagro...(Measuring Light: The important differences between PPF and PPFD)...
...I edited a bit...add more grow areas... ...usuals tent Americans... usual tent Europeans...
This is an Example of How you would Use the PPF to Get an Expected PPFD Value;
Lamp PPF Output : 1,100 µMol / S
Grow Losses off Canopy : 20 % ...then 80 % (,8) Efficiency Used
Light Actually Used : 1,100 x ,8 = 880 µMol / S
Grow Area : 4’ x 4’ = 16 sq-ft = 1,49 M2
Sample Average PPFD Formula: 880 µMol / S ÷ 1,49 M2 = 590,60 µMol / M2 S
Grow Area : 4’ x 4’ = 16 sq-ft = 1,48644864 M2
Sample Average PPFD Formula: 880 µMol / S÷ 1,486 M2 = 592,19 µMol / M2 S
Grow Area : 3’ x 3’ = 9 sq-ft = 0,84 M2
Sample Average PPFD Formula: 880 µMol / S ÷ 0,84 M2 = 1047,62 µMol / M2 S
Grow Area : 3’ x 3’ = 9 sq-ft = 0,83612736 M2
Sample Average PPFD Formula: 880 µMol / S ÷ 0,836 M2 = 1052,63 µMol / M2 S
Grow Area : 2’ x 2’ = 4 sq-ft = 0,37 M2
Sample Average PPFD Formula: 880 µMol / S ÷ 0,37 M2 = 2378,38 µMol / M2 S
Grow Area : 2’ x 2’ = 4 sq-ft = 0,37161216 M2
Sample Average PPFD Formula: 880 µMol / S ÷ 0,371 M2 = 2371,97 µMol / M2 S
Grow Area : 1,5 M x 1,5 M = 2,25 M2
Sample Average PPFD Formula: 880 µMol / S ÷ 2,25 M2 = 391,11 µMol / M2 S
Grow Area : 1,2 M x 1,2 M = 1,44 M2
Sample Average PPFD Formula: 880 µMol / S ÷ 1,44 M2 = 611,11 µMol / M2 S
Grow Area : 1 M x 1M = 1 M2
Sample Average PPFD Formula: 880 µMol / S ÷ 1 M2 = 880 µMol / M2 S
pd... ....upsss... ...for W PAR take the Watts Dissipated (Vf * If @ XXºC = Watts Dissipated @ XXºC) by the leds and multiply it by their Efficiency, and you will get PAR Watts.
...A good rule of thumb is to use 12 W / sqft PAR for 2 - 3 foot plants, 14 – 18 W / sqft PAR for taller.
So if you have a 400 W Dissipation lamp that is 50 % efficient, it will be 200 W of PAR.
400 (Vf * If = Watts Dissipated) * 0.5 Efficiency = 200 PAR Watts
Another 400 W Dissipation lamp that's 35 % Efficient would be 140 W of PAR
400 (Vf * If = Watts Dissipated) * 0.35 Efficiency = 140 PAR Watts
Saludos