eatled
Active Member
Absolutely not.So YOU believe adding a resistor will give you more power than running an open circuit?
The HLG Type B has a pair of dimmer wires. If you connect a 100K Ω pot to these wires you can adjust the output between full power and nearly off.
If you put a 10K Ω resistor the output will be at 10% and 90K Ω 90%.
If you leave the wires disconnected or the are attached to a resistance equal to or greater than 100KΩ the HLG will operate at full power.
If the pot is set at 100 K Ω and you add 10 K Ω, the additional resistor will does nothing.
What the 10 K Ω resistor will do is limit the minimum resistance to 10 K when the pot is set at zero ohms. This means the minimum output is 10% or 32 W for this 320 W HLG.
Below is the schematic of the pot connect to the HLG
The graph shows the amount of resistance across the dimmer wires and the corresponding output current percentage of max current.