A driver is just a constant current power supply. It will adjust its output voltage to "drive" the current at the rated level if the circuit's resistance changes for some reason. Wall warts are typically constant voltage power supplies, so they will increase or decrease the output current as determined by the overall resistance of the circuit.
Soirry bro, i just learned how to use a computer. this is all new to me, im old, i can build a house, an elevator, plumbing, etc but computers out of my league i dont even know what a driver is!! but thanks for the tip!!
In general, diodes are used to control the direction of current flow, however in an LED, there is a much greater voltage drop across the diode because its main function is to produce light.
So, for an LED circuit in series, you will want a constant current power supply (driver) so that the brightness of the LED remains more or less constant, as it will be primarily determined by the current being driven through the diode(ignoring temperature effects). They have a finite resistance, so there will be a certain voltage required to generate the current that powers the LED. All the COBs in the series circuit will have the same current driven through them.
If you want to wire them in parallel, then I think a constant voltage power supply would then be appropriate, but I'm not getting into that.
For series circuits, of diodes, first look at the data sheet to decide on your current. Then, if you don't have a multimeter, use the Vf vs. I chart and the equation V= IR to estimate R.
Next, go to your favorite power supply provider, and find all the power supplies that give your desired current.
Figure out how many COBs you want to power with the circuit, and multiply R by that number, giving the total resistance of the circuit. For series circuits, resistances add. Next, multiply R_tot and I_desired to find the voltage drop of the circuit.
Next, look at the maximum operating current, I_max, of the diodes, and figure out the minimum resistance associated with your circuit in the same way you figured out R_tot. Calculate V_max by V_max = I_max/R_minimum
Pay attention to the Vf vs. T chart, or the Vf vs I (T) chart. Is your system able to properly cool your desired setup? (not my expertise, thus I go for overkill)
Now, go back to your constant current power supply list, and find one with a maximum output voltage that is 80% or less than this V_max number(I chose 80% to be safe, you can go higher but not higher than V_max). Purchase this power supply, wire, and your COBs.
If you can't find a power supply with a low enough V_max output, then take the difference of V_max_psoutput - V_max_your_circuit, and find the value of the current limiting resistor that you will have to add to your circuit (after the cobs) by using R_current_limiting = V_diff/I_desired.
Now, hook up the + output of the power supply to the + terminal on the first cob. Place a jumper wire from the - terminal of this COB to the + terminal of the next COB. Repeat jumper wires until you get to the last COB. Connect the negative terminal of the last COB to your current limiting resistor, connect the other side of the resistor to the - terminal of the power supply. Plug in.
I think this the way to do it anyway, if it's incorrect, please fix me!! This is how I would do it, lol.
Here's the 3070 datasheet:
www.cree.com/~/media/Files/Cree/LED%20Components%20and%20Modules/XLamp/Data%20and%20Binning/ds%20CXA3070.pdf