http://www.solartechnology.co.uk/support-centre/calculating-your-solar-requirments
**The power generation rating of a Solar panel is also given in Watts (e.g. our part number STP010, is a 10W solar panel). In Theory, to calculate the energy it can supply to the battery, you multiply Watts (of the solar panel) by the hours exposed to sunshine.
In practice it’s not a great way to calculate the output from a solar panel so we work to a few simple rules.
· We would generally advise that an average UK winters day will only give you 1 hours sunshine
· An average UK summers days will give you 6 hours of sunshine.
So in winter a 10w panel will provide 10w worth of energy back into your battery. (10w x 1 = 10w)
In Summer a 10w panel will provide 60w worth of energy back into your battery. (10w x 6 = 60w)
Using the above calculation takes into consideration any losses in the system from the regulator, cables and battery you may be using.**
So using those as a rough guide your max daily wattage from your 400w x 3 array will be 1200 x 6 = 7200 W/hrs or 7.2 KW/hrs high summer and about 1.2 KW/hrs mid winter before inversion. You would be best off running dc -dc with a buck converter to regulate the voltage. I would use a series wireing on both my panels and my batteries so assuming your panels are rated at 12v nominal and push around 20v off load then you can series them to for a 36v on load supply and feed them into sets of 3 batteries then use 36-40v cobs. If you adequately cool your cobs then nothing more than a buck converter to ensure stable output voltage with minimal loss would be needed to regulate voltage and over current will be controlled by your thermal regulation of your cobs (big arsed heatsinks) cobs only need current regulation if there is excess voltage or they overheat.
In conclusion; take your minimum solar output, divide by 24hrs then allow 20-30% for storage losses, this will give you your maximum cob array size 1200/24 = 50 x 0.8 = 40 watts
If you invert this then feed drivers with it you will need to lower that number by a further 10-20% for inversion conversion losses. Sorry but it looks like you will need more than 3 x 400w solar panels.