learningthebasics27
Active Member
I’ve never tried air cooling anything that large, but the math should be the same. 3.412 btu per watt of lighting. 550x8=4400 watts but let’s call it a min of 5000 watts because of other equipment. It takes 3.41 but per watt so 3.41x5000= 17050. So the min size AC I’d go with would be 18k btu. I’d go bigger than that tho but I’m not used to led. I am getting a 2 ton mini for 4K watts.
It would def be cheaper to cool 2 10x10 tents run on opposite schedules. Then you only cooling 2200 watts at a time. At that point depending on your home hvac system and or ventilation you use you could possibly not even need extra AC unless it’s really hot where u live. I successfully air cooled 2150 watts in a 4x8 all winter just had to keep the house set on 66 and highest temps I got was 81 and that was with venting back into house for heat. I did close the damper for the hvac to the room it’s in so it didn’t get heated by furnaceand I open it when have AC on. I have dropped down to 1830 watts for now as it’s warming up outside but won’t be a problem in couple weeks when get the mini installed.
The only problem with two tents is you have to buy 2 of everything and can add to intial cost.
So it looks like if I went the 10x20 route I would have to get a mini split AC? Where as if I went the 10x10 route I could just throw 12k btu portable AC in each tent rather than cooling the whole room for the 10x20. The room the 10x20 would be in has vaulted ceilings and stuff. But if I have the AC inside the tent with an exhaust going and fresh air wouldnt it just exhaust out the cool air?