stardustsailor
Well-Known Member
Well...
I'm not able to go to sleep ,tonight ...
So -just for the fun of it- made a new tool ...
A spreadsheet that calculates how many grams of CO2 your plant(s) fix per light cycle .
How it works :
Basically it multiplies the RQE McCree curve with the Cannabis L. Sativa absorptance spectrum.
The result is ,what I like to call " Photosynthetic Potentional " ak PP .
Then the spreadsheet multiplies PP with the light source's umol/nm (at a given power ).
The result is how many of these photons are used to fix carbon molecules per light cycle ...
As an example I've used the Cree CXB 3590 3000°K 80Ra 36V type,bin CB .
Driven at 1400 mA ( 1.4 A )
Assuming that all the emitted photons are being incident to leaf canopy ....
Then this particular COB has an PP efficiency of 74.12 % ( meaning that from all the photons emitted ,
that percentage is actually being used for carbon fixation ) and during the 12 hour light course ,
16.1 grams of CO2 are being fixed ( per single COB unit ) or if you prefer that in volume ,then
it will be 8,196 liters of CO2
I'm not able to go to sleep ,tonight ...
So -just for the fun of it- made a new tool ...
A spreadsheet that calculates how many grams of CO2 your plant(s) fix per light cycle .
How it works :
Basically it multiplies the RQE McCree curve with the Cannabis L. Sativa absorptance spectrum.
The result is ,what I like to call " Photosynthetic Potentional " ak PP .
Then the spreadsheet multiplies PP with the light source's umol/nm (at a given power ).
The result is how many of these photons are used to fix carbon molecules per light cycle ...
As an example I've used the Cree CXB 3590 3000°K 80Ra 36V type,bin CB .
Driven at 1400 mA ( 1.4 A )
Assuming that all the emitted photons are being incident to leaf canopy ....
Then this particular COB has an PP efficiency of 74.12 % ( meaning that from all the photons emitted ,
that percentage is actually being used for carbon fixation ) and during the 12 hour light course ,
16.1 grams of CO2 are being fixed ( per single COB unit ) or if you prefer that in volume ,then
it will be 8,196 liters of CO2
Cheers.Notes :
1 mol CO2 = 10^6 umols CO2 = 44 grams = 22.4 liters @ 25°C ,1 atm
1 mol CO2 needs 10 mols of quanta to be fixed. )
To play with it you will need :
a ) The digitized Rel. Spectral Power Distribution graph of a COB into y values .
Place them at the amber column of the tool named " RSPD "
b ) Using Cree PCT or a digitizer & spec datasheet plots of Vf vs If & output vs Io ,
you will have to enter the Vf and lumens output of the given COB at a given current .
Also enter the number of COBs used as also the light duration.
( enter values at the amber colored cells )
c) The spreadsheet needs OpenOffice (free download ) in order to work ...
d ) At cyan colored cells you get the results .
Have fun.
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