Khronickush
Well-Known Member
Do i have to use a 240v power cord with my 1000watt digital ballast to power my 1000watt HPS bulb or would the 120 cord work also? also when i ordered my ballast it only came with the one 120v cord. help appreciated
No. Because of increased voltage. Watts = Volts x Amps.4.333 times 240 divided by 1000 =0.999KW AND
8.333 times 120 divided by 1000 =0.999kw
said it before and I'll say it again, HOW does this math add up if it is only using half the amps?
Because it uses half the amps per hot leg.
and how do you increase voltage? You add another hot leg, so you have 2 120v hot legs. each 1 carries half the amps of SINGLE 120v line. According to you guys, if you run 240 you are only using half the amps, so each leg only carries 2.166 amps per leg, and if that was the case, it would be half the cost to run a ballasts on 240v, WELL, that isn't true, look at my math above, we get charged by KW's and the math to achieve KW"S is amps x voltage / 1000= KWNo. Because of increased voltage. Watts = Volts x Amps.
When it is known what the applied voltage is, the amperage through a circuit will be govern by the resistance (or impedance) of the load. While we all agree that wattage is defined as the power consumed, wattage can also be defined as the rate that electrical energy is transferred through a circuit. One watt of electrical energy is one joule per second. If it can be said that voltage is the force behind electrons flow, and that current is the volume of electrons flow through a circuit...Then it could also be said that if we increase the force (voltage), the volume of electrons flow (amps) will also increase, This would also result in an increase of power consumed (wattage). To counteract this increase of wattage, the impedance or resistance (ohms) of the internal circuitry inside the ballast must be increased, resulting in fewer amps to flow through the circuit.4.333 times 240 divided by 1000 =0.999KW AND
8.333 times 120 divided by 1000 =0.999kw
said it before and I'll say it again, HOW does this math add up if it is only using half the amps?
Because it uses half the amps per hot leg.