I can't get a straightforward answer on google, here's the example I see for a 38 watt...
Converting the 'va' to amps gives: 40va / 24v = 1.6 amps. Converting to watts gives: 1.6 x 24 = 38.4 watts...
That doesn't mean anything to me, I need one to run a 150w fan, how many watts or amps equals 500va ?
VA = watts when PFC equals 1. Short story is max its rated for is 500W but if your load is inductive (like a fan) or capacitive then it'll be less because of the phase lag/lead. It'll be plenty to run 1, 150W fan.
Edit - I mean power factor, not power factor correction. Power factor correction is circuitry to make inductive or capacitive loads operate at ~1 power factor. Power factor is the ratio of average load wattage compared to input RMS V·A. If you remember that volts × amps = watts then you can understand how power factor impacts load wattage.
If V × A = wattage, then you can see that instantaneous wattage increases and decrease as the voltage and/or current rises and falls, and you can also see that in the graph where peak V aligns with peak A (1st), that the average wattage for the entire period will be greater compared to the average wattage for the entire period for the lagging & leading current graphs (2nd & 3rd; peak current aligns with less than peak V in out of phase circuits, so peak wattage is less compared to when the peaks align, ie power factor of 1), and you can see how lagging or leading reduces optimal wattage given a supplied voltage and load resistance.
As a capacitor fills with charge (the voltage in the cap increases) the differential in supply voltage and oppositional voltage (in the cap) becomes smaller and smaller, and thus the current slows more and more, so this means the current is greatest for a capacitor when its just beginning to charge, and the current reduces as the voltage in the cap increases.
Inductors are the exact opposite, as time progresses the inductor reduces impedance and the current increases, so with an inductor the current is least when the voltage is applied, though as time progresses the current increases to the point it acts like a short after enough time has surpassed.
