Search results

Just got prices from Jimmy and I've narrowed it down to 2 choices, but I am very much leaning towards the 1.75A option. The price difference between the 1.4A & 1.75A drivers is only AU$32 and my PPFD will jump from [email protected] to [email protected]? Plan is to buy a Model B Driver and have a remote...

I've been trying to calculate the performance of the Fastron H42 heatsink but I am unsure as to which cm²/HeatW value to use. I've seen values ranging from 110cm² for HeatsinkUSA's 5.886 profile to 160cm² for Conrad's M18 profile. Specifically for H24, I've seen both 120cm² and 160cm² used in...

Generally speaking, would a CXB3590 stuck to a good CPU cooler, such as the Arctic 64 Plus, run cooler than being stuck to a suitably sized passive heatsink, and to what degree would the performance of the COB differ as a result? Thanks.

I don't know if anyone has posted this previously, but by transposing Supara's formula we can calculate the required length of any known heatsink given a target HeatW using the following formula. Note that all measurements are in millimetres. Length = TargetHeatW * cm²/HeatW * 10 / (...

Is that for the Milled H42 or rough? Thanks.

Thanks. Email sent to Jerry and reply received. He said he only sells drivers to people who purchase COBS from him, but his minimum quantity for sale is 5 COBS. So I replied asking if he was prepared to sell less COBS on the proviso that I also purchase the matching driver. Hopefully he says...

I've heard that Jerry at Kingbrite is the man to go to for cheap CREE COBs from China. Is there an equivalent for cheap Mean Well drivers from China? Thanks

Hey Zulunature, I'm interested in the Fastron H42 profile heatsink, and I'm not clear as to what cost $175. Is that what it cost for a 1000mm length of the Milled H42? Yep, thought of U Channel as well. Here's the results: And this is a sheet of 6.35mm 6061 T651 Mill alloy which is 40mm...

Alas. The root cause of my insomnia since I started down this rabbit hole.

I'm currently looking at cooling requirements. Cooling them, be it actively or passively, is proving to be quite costly if you live in Australia. Our range is limited, and what is available generally costs about 3 times as much as in the USA. And if I purchase from anywhere OS, then shipping...

I hadn't planned on using reflectors/lenses. Are they required? I'm investigating heatsinks at present and being in Australia really limits my choices, and what's available is really pricey compared to what you guy in the US get from HeatsinkUSA. At this stage less COBS will be better. Still...

HLG-240H-C1400 driving 14 x CXB2530 @ 0.7A for $204.12 (excluding driver) That's a lot of grunt for just over $200. Overkill?

I haven't read through this entire thread but I did find Supra's formula for calculating the surface area of a heatsink in order to know how many watts it can dissipate. Would it be feasible to use a flat aluminium sheet as a heatsink, say 5mm thick, and would the formula still apply? After...

Is there a point of diminishing returns with PPFD values? If I recall correctly, 1200 PPFD seems to be the target we aim for. Less isn't as good, but what happens with more? Rahz, you said earlier "Ideally, in a 6 foot area, 8 3590s ran on a HLG-185H-C700B. (killing it with 200 watts)" This...

I need some additional information in order to continue my decision process. My original design was to limit the flowering chamber to a height of 4 feet. After having a few people mention that 4 feet was quite restrictive, I changed the design of the cabinet so I would end up with 5 feet of...

Thanks everyone, especially Rahz, for your patience and understanding as I went through the exercise of figuring all this this out. I now understand the meaning of all the data within the spreadsheet and have a much better appreciation of the suggestions you have all been proposing. Your...

Nope. Still can't get 146.55W for 3 * CXB3590 @ 1.4A My formula before this change for W/Feet² was: =($N$8*G13*)/$P$4 and now is =($N$8*(G13*$N$)/$P$4 where: $N$8 = #COB G13 = 50c diss/W $P$4 = Area in Feet² So I went from: #COB * 50c diss/W / Area in Feet² to #COB * (#COB * 50c...

OK. If your statement #cobs * 50c%, replace 50c% with 50c dissW. was referring to my W/Feet² calculation, then I have moded the spreadsheet accordingly, and my PAR(W) Total & Heta Watts line up with your results. Can't see 146.55 Watts anywhere.

DAMN. You're too quick with your last post. Give me a minute.