@CobKits
With my current design:
680 CoB W/16SQ = 42.5 CoBW/SQ
42.5 CoB W/SQ @ 45.65% = 19.15 PAR W/SQ
20 PAR W/SQ = 900 PPFD
If 20 = 1, then 19.15 = 0.9575
900 PPFD multiplied by 0.9575 = 861.75 PPFD
Is PPFD in this instance our estimate for real world, or is this PPFD 'units'?
Thanks!
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EDIT: This is not accounting for driver efficiency. These numbers are probably more realistic at a 10% performance reduction:
680 x .90 = 612 CoB W/16SQ = 38.25 CoB W/SQ
38.25 @ 45.65% = 17.24 PAR W/SQ
17.24 PAR W/SQ = 86%(0.86) relative to 20 PAR W/SQ.
900 PPFD multiplied by 0.86 = 775.6 PPFD
When guesstimating 20 PAR W/SQ = 900 PPFD, are you accounting for driver efficiency?
With my current design:
680 CoB W/16SQ = 42.5 CoBW/SQ
42.5 CoB W/SQ @ 45.65% = 19.15 PAR W/SQ
20 PAR W/SQ = 900 PPFD
If 20 = 1, then 19.15 = 0.9575
900 PPFD multiplied by 0.9575 = 861.75 PPFD
Is PPFD in this instance our estimate for real world, or is this PPFD 'units'?
Thanks!
------------------------------------------------------------------------------------------------------------
EDIT: This is not accounting for driver efficiency. These numbers are probably more realistic at a 10% performance reduction:
680 x .90 = 612 CoB W/16SQ = 38.25 CoB W/SQ
38.25 @ 45.65% = 17.24 PAR W/SQ
17.24 PAR W/SQ = 86%(0.86) relative to 20 PAR W/SQ.
900 PPFD multiplied by 0.86 = 775.6 PPFD
When guesstimating 20 PAR W/SQ = 900 PPFD, are you accounting for driver efficiency?
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