The Loafter
Well-Known Member
assuming my 4lx4wx6 tent needs 480 watts (30 watts/ sq foot), would the same tent on its side - 6lx4wx4h still need just 480 watts
IT'S NOT A GASphotons contained in a tent though.
sure it isn't. but photons bounce apparently. less headroom to bounce off
sure it isn't. but photons bounce apparently. less headroom to bounce off
Im assuming in my scenario same watteage for cu ft. so 480 watts at 4x4x6 = 4x6x4 at 480 wattsbut my thought is we will stuff need at least 30wsf based on footprint. although less efficient older diodes should balance things out. dont know how scientific it is. but seems to make sense to me.
Im assuming in my scenario same watteage for cu ft. so 480 watts at 4x4x6 = 4x6x4 at 480 watts
goes from 30 w/ft to 20w/ft
does anyone have some dialux ies files i can play with. I haven't tried yet.
beer delivery came at 7:15 this morning btw.
they project at 120degrees. assuming the light faces down then yeah it projects down, and sideways.Again
It's the footprint or SF the light covers. Lights don't go UP, they project down
4x4 = 16sf
4x6= 24sf
Again
It's the footprint or SF the light covers. Lights don't go UP, they project down
4x4 = 16sf
4x6= 24sf
In theory yes
But dimmed down you won't get the penetration as you will at full blast and a bit higher up
i see 480 being a bit low even on a 4x4. another 10% would be nice but w/e.
its the same volume anyhow, and there would be less headroom to waste energy or reflection.
assuming its just sq ft that matter. do we really need 4x4x6 tents or can we save waste and use 4x4x4 instead?