simple breeding question

hello had a simple question that i cant figure out ok i have 2 plants i breed them the children are f1 so so get f2 and 3 4 to eventually make a stable strain
so how do i make the f2 do i breed 2 of the f1 or do i breed them back to a mother father i know its simple but i havent seen it so if some one would be so kind

f2 are feminized seeds, from what i know. if u breed 2 plants together ( 1 male with 1 female ) the result will be an s1. if u use say GA3 to induce hermaphrodite male flower on your female plant, (on 1 branch say) the pollen it produces is used on a clone from that same plant. The result will be female 99% and therefore be a f1. to make these f1 (female first cross) more stable best way is to grow 100 of the seeds, (that are produced from the hermie pollen and the female the pollen came from, min.) Pick the best 1, use that as your f1 and back cross with the same pollen.(From parent plant) and repeat this process 4 or 5 times.
look im not 100% on this . i'm new to breeding and am not sure i understand it right but if i have this should help. no doubt someone else will let us know.

madazz

madazz demonstrates a good point even though he's obviously off base regarding your desired knowledge..
The terminology out there is pretty dang wishy-washy even among the scientific community.. Basically depending what you're reading, both may be the case..
Personally I like the terminolgy where an F2 cross is a cross between 2 heterozygous F1's from the same parent stock.. This would clearly denote an F2 as untampered, 75%Dom phenotyped sibling stock..
Its worth noting though, that assuming homzygous true breeding parents, back-crossing at this point would not alter the expected phenotypes, only their frequency (which tell you whether that parent is hymozyous dominant or recessive for that trait).. Anything producing some seeds expressing recessive phenotype will prove that the parent was recessive, and in an idealized situation will be homozygous recessive itself, and any dominant phenos will still carry unknown genotype..
AAxAa > AA Aa (100% pheno occurance in backcrossing discovers P1 to be dominant)
aaxAa > Aa aa Aa aa (50% in backcrossing reveals P1 recessive)
AaxAa > AA Aa Aa aa (75% in F1 crossing)

So it doesn't really make a difference since prior to the time they're grown out, the genotype could not be known either way, and after this point you'll know whether they were for all intents and purposes the same as true F2's (F2's and [r]B1's) or backcrossed to the dominant parent ([d]B1's)..