iblazetoomuch
Active Member
Since I've added 400w to the 150w I've been trying to figure out what my lumens at plant canopy was roughly. While I was reading up on inverse square law and I am slightly confused; I used rough estimate of 71,000 lumens at 21 inches n 23 inches away from plant canopy, divided by 4 for 2x2 area (still small plants), then took the 17,750 lumens sq/ft and times by .25 for 1/4th intensity at 2 feet away, my final estimate came out to 4,437.5 lumen sq/ft using init lumen output ratings ect, quite short of my 7-10k desired lumen output; however the confusing part is after reading this on wiki:
Does this mean 1367 watts per square meter (3 feet by 3 feet) and 93 lumens per watt for sunlight = 127,000 lumens over a 9 foot area for the sun??? Lol? I failed math class just as a disclaimer but wtf.
So is my estimate of 4,500 lumens sq/ft accurate estimate? Also is this accurate estimate of lumen output of sun?
For example, the intensity of radiation from the Sun is 9126 watts per square meter at the distance of Mercury (0.387 AU); but only 1367 watts per square meter at the distance of Earth (1 AU)an approximate threefold increase in distance results in an approximate ninefold decrease in intensity of radiation.
Does this mean 1367 watts per square meter (3 feet by 3 feet) and 93 lumens per watt for sunlight = 127,000 lumens over a 9 foot area for the sun??? Lol? I failed math class just as a disclaimer but wtf.
So is my estimate of 4,500 lumens sq/ft accurate estimate? Also is this accurate estimate of lumen output of sun?
